Problem:
A binary operation β has the properties that aβ(bβc)=(aβb)β
c and that aβa=1 for all nonzero real numbers a,b, and c. (Here the dot β
represents the usual multiplication operation.) The solution to the equation 2016β(6βx)= 100 can be written as qpβ, where p and q are relatively prime positive integers. What is p+q?
Answer Choices:
A. 109
B. 201
C. 301
D. 3049
E. 33,601
Solution:
From the given properties, aβ1=aβ(aβa)=(aβa)β
a= 1β
a=a for all nonzero a. Then for nonzero a and b,a=aβ1=aβ(bβb)= (aβb)β
b. It follows that aβb=baβ. Thus
100=2016β(6βx)=2016βx6β=x6β2016β=336x
so x=336100β=8425β. The requested sum is 25+84=(A)109β.
The problems on this page are the property of the MAA's American Mathematics Competitions