Problem:
If nβ‘m=n3m2, what is 4β‘22β‘4β?
Answer Choices:
A. 41β
B. 21β
C. 1
D. 2
E. 4
Solution:
4β‘22β‘4β=43β
2223β
42β=42β=(B)21ββ
The problems and solutions on this page are the property of the MAA's American Mathematics Competitions