Problem:
What is the value of
(((2+1)β1+1)β1+1)β1+1?
Answer Choices:
A. 85β
B. 711β
C. 58β
D. 1118β
E. 815β
Solution:
Computing inside to outside yields:
(((2+1)β1+1)β1+1)β1+1β=((34β)β1+1)β1+1=(47β)β1+1=(B)711ββ.β
Note: The successive denominators and numerators of numbers obtained from this pattern are the Lucas numbers.
The problems on this page are the property of the MAA's American Mathematics Competitions