Problem:
In the rectangular parallelepiped shown, AB=3,BC=1, and CG=2. Point M is the midpoint of FG. What is the volume of the rectangular pyramid with base BCHE and apex M?
Answer Choices:
A. 1
B. 34β
C. 23β
D. 35β
E. 2
Solution:
The volume of the rectangular pyramid with base BCHE and apex M equals the volume of the given rectangular parallelepiped, which is 6, minus the combined volume of triangular prism AEHDCB, tetrahedron BEFM, and tetrahedron CGHM. Tetrahedra BEFM and CGHM each have three right angles at F and G, respectively, and the edges of the tetrahedra emanating from F and G have lengths 2,3, and 21β, so the volume of each of these tetrahedra
is 61ββ (2β 3β 21β)=21β. The volume of the triangluar prism AEHDCB is 3 because it is half the volume of the rectangular parallelepiped. Therefore the requested volume is 6β3β21ββ21β=(E)2β.
OR
Let P and Q be the midpoints of BC and EH, respectively. By the Pythagorean Theorem PQ=13β. Let R be the foot of the perpendicular from M to PQβ. Then β³PMQβΌβ³PRM, so
13β3β=PQMQβ=PMRMβ=2RMβ and RM=13β6β
The requested volume of the pyramid is 31β times the area of the base times the height, which is