Problem:
What value of x satisfies
x−43=125−31?
Answer Choices:
A. −32
B. 367
C. 127
D. 32
E. 65
Solution:
Adding 43 to both sides:
x=125−31+43=125−124+129= (E) 65
OR
Multiplying 12 on both sides gets us:
12x−9=1⟹12x=10
Therefore x=(E)65.
The problems on this page are the property of the MAA's American Mathematics Competitions