Problem:
Call a fraction baβ, not necessarily in the simplest form special if a and b are positive integers whose sum is 15. How many distinct integers can be written as the sum of two, not necessarily different, special fractions?
Answer Choices:
A. 9
B. 10
C. 11
D. 12
E. 13
Solution:
The special fractions are
141β,132β,123β,114β,105β,96β,87β,78β,69β,510β,411β,312β,213β,114ββ
141β,132β,41β,114β,21β,32β,87β,171β,121β,2,243β,4,621β,14β
Note that two unlike fractions in the simplest form cannot sum to an integer. So, we only consider the fractions whose denominators appear more than once:
41β,21β,121β,2,243β,4,621β,14β
For the set {2,4,14}, two elements (not necessarily different) can sum to 4,6,8,16,18,28.
For the set {21β,121β,621β}, two elements (not necessarily different) can sum to 1,2,3,7,8,13.
For the set {41β,243β}, two elements (not necessarily different) can sum to 3
Together, there are (C) 11β distinct integers that can be written as the sum of two, not necessarily different,
special fractions:
1,2,3,4,6,7,8,13,16,18,28.
The problems on this page are the property of the MAA's American Mathematics Competitions