Problem:
What is the value of
(3xβ2)(4x+1)β(3xβ2)4x+1
when x=4 ?
Answer Choices:
A. 0
B. 1
C. 10
D. 11
E. 12
Solution:
Since
(3xβ2)(4x+1)β(3xβ2)4x+1=(3xβ2)(4x+1β4x)+1=(3xβ2)β
1+1=3xβ1β
when x=4 we have the value 3β
4β1=11β.
The problems on this page are the property of the MAA's American Mathematics Competitions