Problem:
For all positive integers n less than 2002 , let
anβ=β©βͺβͺβͺβͺβ¨βͺβͺβͺβͺβ§β11, if n is divisible by 13 and 1413, if n is divisible by 14 and 1114, if n is divisible by 11 and 130, otherwise β
Calculate βn=12001βanβ.
Answer Choices:
A. 448
B. 486
C. 1560
D. 2001
E. 2002
Solution:
Since 2002=11β
13β
14, we have
anβ=β©βͺβͺβͺβͺβ¨βͺβͺβͺβͺβ§β11, if n=13β
14β
i, where i=1,2,β¦,1013, if n=14β
11β
j, where j=1,2,β¦,1214, if n=11β
13β
k, where k=1,2,β¦,130, otherwise β
Hence βn=12001βanβ=11β
10+13β
12+14β
13=448β.
The problems on this page are the property of the MAA's American Mathematics Competitions