Problem:
Which of the following is the same as
3β6+9β12+15β18+212β4+6β8+10β12+14β?
Answer Choices:
A. β1
B. β32β
C. 32β
D. 1
E. 314β
Solution:
We have
3β6+9β12+15β18+212β4+6β8+10β12+14β=3(1β2+3β4+5β6+7)2(1β2+3β4+5β6+7)β=32ββ
The problems on this page are the property of the MAA's American Mathematics Competitions