Problem:
Which of the following is equal to the product
48ββ
812ββ
1216ββ―4n4n+4ββ―β
20042008β?
Answer Choices:
A. 251
B. 502
C. 1004
D. 2008
E. 4016
Solution:
Because each denominator except the first can be canceled with the previous numerator, the product is 42008β=502β.
The problems on this page are the property of the MAA's American Mathematics Competitions