Problem:
Let a+ar1β+ar12β+ar13β+β― and a+ar2β+ar22β+ar23β+β― be two different infinite geometric series of positive numbers with the same first term. The sum of the first series is r1β, and the sum of the second series is r2β. What is r1β+r2β?
Answer Choices:
A. 0
B. 21β
C. 1
D. 21+5ββ
E. 2 Solution:
The sum of the first series is
1βr1βaβ=r1β
from which r12ββr1β+a=0, and r1β=21β(1Β±1β4aβ). Similarly, r2β=21β(1Β±1β4aβ). Because r1β and r2β must be different, r1β+r2β=1β. Such series exist as long as 0<a<41β.