Problem:
What is (20β(2010β201))+(2010β(201β20))?
Answer Choices:
A. β4020
B. 0
C. 40
D. 401
E. 4020
Solution:
Distributing the negative signs gives
(20β(2010β201))+(2010β(201β20))=20β2010+201+2010β201+20=40β.β
The problems on this page are the property of the MAA's American Mathematics Competitions