Problem:
The average of the numbers 1,2,3,β¦,98,99, and x is 100x. What is x ?
Answer Choices:
A. 10149β
B. 10150β
C. 21β
D. 10151β
E. 9950β
Solution:
The average of the numbers is
"No"
1001+2+β―+99+xβ=100299β
100β+xβ=10099β
50+xβ=100x
This equation is equivalent to 9999x=(99β
101)x=99β
50, so x=10150ββ.
The problems on this page are the property of the MAA's American Mathematics Competitions