Problem:
When p=βk=16βklnk, the number ep is an integer. What is the largest power of 2 that is a factor of ep ?
Answer Choices:
A. 212
B. 214
C. 216
D. 218
E. 220
Solution:
Because klnk=ln(kk) and the log of a product is the sum of the logs,p=lnβk=16βkk. Therefore ep is the integer 11β
22β
33β
44β
55β
66=216β
39β
55, and the largest power of 2 dividing ep is 216β.
The problems on this page are the property of the MAA's American Mathematics Competitions