Problem: What is the value of (20−1+52+0)−1×5\left(2^{0}-1+5^{2}+0\right)^{-1} \times 5(20−1+52+0)−1×5 ?
Answer Choices:
A. −125-125−125 B. −120-120−120 C. 15\dfrac{1}{5}51 D. 524\dfrac{5}{24}245 E. 252525 Solution:
(1−1+25+0)−1×5=125×5=15(1-1+25+0)^{-1} \times 5=\dfrac{1}{25} \times 5= \boxed{\dfrac{1}{5}} (1−1+25+0)−1×5=251×5=51
The problems on this page are the property of the MAA's American Mathematics Competitions