Problem:
Quadrilateral ABCD is inscribed in a circle with β BAC=70β,β ADB=40β, AD=4, and BC=6. What is AC ?
Answer Choices:
A. 3+5β
B. 6
C. 29β2β
D. 8β2β
E. 7 Solution:
Because β BAC and β BDC intercept the same arc, β BDC=70β. Then β ADC=110β and β ABC=180βββ ADC=70β. Thus β³ABC is isosceles, and therefore AC=BC=6β.