Problem:
How many ordered pairs (a,b) such that a is a positive real number and b is an integer between 2 and 200, inclusive, satisfy the equation (logbβa)2017=logbβ(a2017)?
Answer Choices:
A. 198
B. 199
C. 398
D. 399
E. 597 Solution:
Let u=logbβa. Because u2017=2017u, either u=0 or u=Β±20162017β. If u=0, then a=1 and b can be any integer from 2 to 200 . If u=Β±20162017β, then a=bΒ±20162017β, where again b can be any integer from 2 to 200 . Therefore there are 3β 199=597β such ordered pairs.