Problem:
Ajay is standing at point A near Pontianak, Indonesia, 0β latitude and 110βE longitude. Billy is standing at point B near Big Baldy Mountain, Idaho, USA, 45βN latitude and 115βW longitude. Assume that Earth is a perfect sphere with center C. What is the degree measure of β ACB ?
Answer Choices:
A. 105
B. 11221β
C. 120
D. 135
E. 150 Solution:
To travel from A to B, one could circle 135β east along the equator and then 45β north. Construct an xβyβz coordinate system with origin at Earth's center C, the positive x-axis running through A, the positive y-axis running through the equator at 160β west longitude, and the positive z-axis running through the North Pole. Set Earth's radius to be 1 . The coordinates of A are (1,0,0). Let b be the y-coordinate of B; note that b>0. Then the x-coordinate of B will be βb, and the z-coordinate will be 2βb. Because the distance from the center of Earth is 1,
(βb)2+b2+(2βb)2β=1
so b=21β, and the coordinates are (β21β,21β,22ββ). The distance AB is therefore
(23β)2+(21β)2+(22ββ)2β=3β
Applying the Law of Cosines to β³ACB gives
3=1+1β2β 1β 1β cosβ ACB
so cosβ ACB=β21β and β ACB=120ββ. An alternative to using the Law of Cosines to find cosβ ACB is to compute the dot product of the unit vectors (1,0,0) and (β21β,21β,22ββ).