by using the quadratic formula on each of the quadratic factors. Since the first four roots are all distinct, the term (x2−cx+4) must be a product of any combination of two (not necessarily distinct) factors from the set: (x−[1−i]),(x−[1+i]),(x−[2−2i]), and (x−[2+2i]). We need the two factors to yield a constant term of 4 when multiplied together. The only combinations that work are (x−[1−i]) and (x−[2+2i]), or (x−[1+i]) and (x−[2−2i]). When multiplied together, the polynomial is either (x2+[−3+i]x+4) or (x2+[−3−i]x+4). Therefore, c=3±i and ∣c∣= (E)10.