Problem:
Two distinct numbers are selected from the set {1,2,3,4,β¦,36,37} so that the sum of the remaining 35 numbers is the product of these two numbers. What is the difference of these two numbers?
Answer Choices:
A. 5
B. 7
C. 8
D. 9
E. 10
Solution:
The sum of the first n integers is given by 2n(n+1)β, so 237(37+1)β=703. Therefore,
703βxβy=xy
Rearranging, xy+x+y=703. We can factor this equation by SFFT to get
(x+1)(y+1)=704
Looking at the possible divisors of 704=26β
11,22 and 32 are within the constraints of 0<xβ€yβ€37 so we try those:
(x+1)(y+1)x+1=22,x=21,β=22β
32 y+1=32 y=31β
Therefore, the difference yβx=31β21=(E) 10β .
The problems on this page are the property of the MAA's American Mathematics Competitions