Problem:
Ms. Blackwell gives an exam to two classes. The mean of the scores of the students in the morning class is 84, and the afternoon class mean score is 70. The ratio of the number of students in the morning class to the number of students in the afternoon class is 43β. What is the mean of the scores of all the students?
Answer Choices:
A. 74
B. 75
C. 76
D. 77
E. 78
Solution:
Let there be 3x students in the morning class and 4x students in the afternoon class. The total number of students is 3x+4x=7x. The average is 7x3xβ
84+4xβ
70β=76. Therefore, the answer is (C) 76β .
OR
Suppose the morning class has m students and the afternoon class has a students. We have the following table:
MorningAfternoonβ# of StudentsmaβMean8470βTotal84m70aββ
We are also given that amβ=43β, which rearranges as m=43βa.
The mean of the scores of all the students is
m+a84m+70aβ=43βa+a84(43βa)+70aβ=47βa133aβ=133β
74β=(C) 76β .
OR
Of the average, 3+43β=73β of the scores came from the morning class and 74β came from the afternoon class. The average is 73ββ
84+74ββ
70=(C) 76β .
The problems on this page are the property of the MAA's American Mathematics Competitions