Recall that x+x1ββ₯2 for all positive real numbers x, with equality if and only if x=1. Therefore the left-hand side of this equation is bounded below by 8+8+8+8, and the only solution occurs when 2a=1 and b=1.
OR
Applying the Arithmetic Mean-Geometric Mean Inequality gives the following statements:
1+2a=21β+21β+a+aβ₯444a2ββ; equality holds if and only if a=21β;
2+2b=1+1+b+bβ₯44b2β; equality holds if and only if b=1;
2a+b=a+a+2bβ+2bββ₯444a2b2ββ; equality holds if and only if b=2a.
Multiplying the three inequalities above gives (1+2a)(2+2b)(2a+b)β₯32ab, and equality holds if and only if a=21β and b=1.