Problem:
For complex numbers u=a+bi and v=c+di (where i=β1β ), define the binary operation
uβv=ac+bdi
Suppose z is a complex number such that zβz=z2+40. What is β£zβ£?
Answer Choices:
A. 2
B. 5
C. 5β
D. 10β
E. 52β
Solution:
Let z=a+bi. Then zβz=a2+b2i and z2=(a2βb2)+2abi, so the original equation is equivalent to
a2+b2i=(a2βb2+40)+2abi
Setting the real parts of both sides equal gives b2=40, so b=Β±210β. Setting the imaginary parts of both sides equal yields a=2bβ=Β±10β. Then
β£zβ£=a2+b2β=10+40β=(E)52ββ
The problems on this page are the property of the MAA's American Mathematics Competitions