Two non-congruent triangles have the same area. Each triangle has sides of length 8 and 9, and the third side of each triangle has integer length. What is the sum of the lengths of the third sides?
Answer Choices:
A. 20
B. 22
C. 24
D. 26
E. 28
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Hence, the following polynomial has least two distinct positive integer roots (namely m and n):
P(x)=β(17+x)(17βx)(x+1)(xβ1)+c
where c is some real number. Note that P(x)=(x2β1)(x2β289)+c=x4β290x2+(289+c) is even, so its four roots are m, βm, n, and βn. Hence m2+n2=290 for some m and n satisfying 1<m,n<17. We can solve this by inspection and see that m and n must be 11 and 13 in some order, which yields a final answer of (C)24β.
Remark: We can verify that the area of a 8β9β11 triangle is the same as the area of a 8β9β13 triangle, namely 635β.