Problem:
The product of the 9 factors (1β21β)(1β31β)(1β41β)β¦(1β101β)=
Answer Choices:
A. 101β
B. 91β
C. 21β
D. 1110β
E. 211β
Solution:
The desired product equals 21βΓ32βΓ43βΓβ¦Γ98βΓ109β=101β Notice that since 21βΓ32β=31β, the product is less than 31β so (C),(D) and (E) are easily eliminated.
Answer: Aβ.
The problems on this page are the property of the MAA's American Mathematics Competitions