Problem:
The sum 271β+321β+5191β is between
Answer Choices:
A. 10 and 1021β
B. 1021β and 11
C. 11 and 1121β
D. 1121β and 12
E. 12 and 1221β
Solution:
The desired sum can be rewritten as 2+3+5+71β+21β+191β which equals 10+21β+(a number less than 21β) so B is correct.
Answer: Bβ.
The problems on this page are the property of the MAA's American Mathematics Competitions