Problem: 110+220+330=\dfrac{1}{10}+\dfrac{2}{20}+\dfrac{3}{30}=101+202+303=
Answer Choices:
A. .1.1.1 B. .123.123.123 C. 222 D. .3.3.3 E. .6.6.6
Solution:
Since 220=330=110\dfrac{2}{20}=\dfrac{3}{30}=\dfrac{1}{10}202=303=101, the desired sum is .1+.1+.1=.3.1+.1+.1=.3.1+.1+.1=.3.
Answer: D\boxed{D}D.
The problems on this page are the property of the MAA's American Mathematics Competitions