Problem:
1−211−31=
Answer Choices:
A. 31
B. 32
C. 43
D. 23
E. 34
Solution:
1−211−31=2132=32×12=34.
OR
Multiplying both numerator and denominator by 6 yields
6(1−21)6(1−31)=6−36−2=34.
Answer: E.
The problems on this page are the property of the MAA's American Mathematics Competitions