Problem:
7Γ539β=
Answer Choices:
A. .7Γ53.9β
B. .7Γ.53.9β
C. .7Γ5.3.9β
D. 7Γ.53.9β
E. .07Γ.53.09β
Solution:
To get .9 in the numerator, we must divide it by 10. To maintain equality, we must also divide the denominator by 10. Thus
107Γ53β109ββ=107βΓ53109ββ=.7Γ53.9β.
In all other cases, the resulting fraction is 101β or 1001β of the original fraction.
Answer: Aβ.
The problems on this page are the property of the MAA's American Mathematics Competitions