Problem: 210+4100+61000=\dfrac{2}{10}+\dfrac{4}{100}+\dfrac{6}{1000}=102+1004+10006=
Answer Choices:
A. .012.012.012 B. .0246.0246.0246 C. 121212 D. .246.246.246 E. 246246246
Solution:
The sum is .2+.04+.006=.246.2+.04+.006=.246.2+.04+.006=.246.
Answer: D\boxed{D}D.
The problems on this page are the property of the MAA's American Mathematics Competitions