Problem:
(2Γ3Γ4)(21β+31β+41β)=
Answer Choices:
A. 1
B. 3
C. 9
D. 24
E. 26
Solution:
Using the distributive law, the product equals
β(2Γ3Γ4)Γ(21β)+(2Γ3Γ4)Γ(31β)+(2Γ3Γ4)Γ(41β)=(3Γ4)+(2Γ4)+(2Γ3)=12+8+6=26.β
Although it is more tedious, one can perform the operations within each set of parentheses to obtain:
24(126β+124β+123β)=24(1213β)=26.
Answer: Eβ.
The problems on this page are the property of the MAA's American Mathematics Competitions