Problem:
If each of the three operation signs,,,+βΓ, is used exactly ONCE in one of the blanks in the expression
5_4_6_3
then the value of the result could equal
Answer Choices:
A. 9
B. 10
C. 15
D. 16
E. 19
Solution:
The six permutations of,+- and Γ yield these results:
β5Γ4+6β3=20+6β3=235Γ4β6+3=20β6+3=175+4Γ6β3=5+24β3=265β4Γ6+3=5β24+3=β165+4β6Γ3=5+4β18=β95β4+6Γ3=5β4+18=19β
The only result listed is 19.
Answer: Eβ.
The problems on this page are the property of the MAA's American Mathematics Competitions