Problem:
1+2+31β1β1β=
Answer Choices:
A. 61β
B. 103β
C. 107β
D. 65β
E. 310β
Solution:
Using the common denominators and simplifying yield
1+2+31β1β1β=1+37β1β1β=1+73β1β=710β1β=107β
OR
Clearing fractions and simplifying yield
1+(2+31β)Γ31Γ3β1β=1+6+13β1β=(1+73β)Γ71Γ7β=7+37β=107β
OR
Estimating, the result is between
1+21β1β=23β1β=32β and 1+31β1β=34β1β=43β
The only choice in this interval is 107β.
Answer: Cβ.
The problems on this page are the property of the MAA's American Mathematics Competitions