Problem:
If β A=20β and β AFG=β AGF, Then β B+β D=
Answer Choices:
A. 48β
B. 60β
C. 72β
D. 80β
E. 90β
Solution:
Since β AFG=β AGF and β GAF+β AFG+ β AGF=180β, we have 20β+2(β AFG)=180β. So β AFG= 80β. Also, β AFG+β BFD=190β, so β BFD=100β. The sum of the angles of β³BFD is 180β, so β B+β D=80β.
Note: In β³AFG,β AFG=β B+β D. In general, an exterior angle of a triangle equals the sum of its remote interior angles. For example, in β³GAF,β x=β GAF+β AGF.
Note that, as in Problem 13, some texts use different symbols to represent an angle and its degree measure.
Answer: Dβ.
The problems on this page are the property of the MAA's American Mathematics Competitions