Problem:
The area of rectangle ABCD is 72. If point A and the midpoints of BC and CD are joined to form a triangle, the area of that triangle is
Answer Choices:
A. 21
B. 27
C. 30
D. 36
E. 40
Solution:
Three right triangles lie outside β³AMN. Their areas are 41β,41β, and 81β for a total of 85β of the rectangle. The area of β³AMN is 83β(72)=27.
OR
Let the rectangle have sides of 2a and 2b so that 4ab=72 and ab=18. Three right triangles lie outside triangle AMN, and their areas are 21β(2a)(b), 21β(2b)(a), 21β(a)(b), for a total of 25β(ab)=25β(18)=45. The area of triangle AMN is 72β45=27.
Answer: Bβ.
The problems on this page are the property of the MAA's American Mathematics Competitions