Problem:
In the figure, ABCD is a rectangle and EFGH is a parallelogram. Using the measurements given in the figure, what is the length d of the segment that is perpendicular to HE and FG?
Answer Choices:
A. 6.8 
B. 7.1 
C. 7.6 
D. 7.8 
E. 8.1 
Solution:
By the Pythagorean Theorem, HE=5. Rectangle ABCD has area 10Γ8=80, and the corner triangles have areas 21βΓ3Γ4=6 and 21βΓ6Γ5=15. So the area of EFGH is 80β(2)(6)β(2)(15)=38. Because the area of EFGH is EHΓd and EH=5,38=5Γd, so d=7.6.
Answer: Cβ.
The problems on this page are the property of the MAA's American Mathematics Competitions