Problem:
What is the correct ordering of the three numbers 108,512, and 224?
Answer Choices:
A. 224<108<512
B. 224<512<108
C. 512<224<108
D. 108<512<224
E. 108<224<512
Solution:
224=(28)⋅(216)=(28)⋅(48)<(28)⋅(58)=108=(44)⋅(58)<(54)⋅(58)=512.
Answer: A.
The problems on this page are the property of the MAA's American Mathematics Competitions