Problem:
What is the correct ordering of the three numbers 195β,217β, and 239β, in increasing order?
Answer Choices:
A. 239β<217β<195β
B. 195β<217β<239β
C. 239β<195β<217β
D. 195β<239β<217β
E. 217β<195β<239β
Solution:
Using a common denominator, 195β=399105β and 217β=399133β, so 195β<217β.
Also 217β=483161β and 239β=483189β, so 217β<239β.
OR
Comparing each fraction, 217β=31β,195β<155β=31β, and 239β>279β=31β, so the correct increasing order is 195β<217β<239β.
Answer: Bβ.
The problems on this page are the property of the MAA's American Mathematics Competitions