Problem:
What is the largest power of 2 that is a divisor of 134β114?
Answer Choices:
A. 8
B. 16
C. 32
D. 64
E. 128
Solution:
Factor, using a difference of two squares:
134β114β=(132+112)(13+11)(13β11)=290β
24β
2=2β
145β
8β
3β
2=32β
435β
So the largest power of 2 that is a divisor of 134β114 is 32.
Answer: Cβ.
The problems on this page are the property of the MAA's American Mathematics Competitions