Problem:
In the figure shown below, choose point D on side BC so that β³ACD and β³ABD have equal perimeters. What is the area of β³ABD?
Answer Choices:
A. 43β
B. 23β
C. 2
D. 512β
E. 25β
Solution:
Because the perimeters of β³ADC and β³ADB are equal, CD=3 and BD=2.
β³ADC and β³ADB have the same altitude from A, so the area of β³ADC will be 3/5 of the area of β³ABC, and β³ADB will be 52β of the area of β³ABC. The area of β³ABC is 21ββ
3β
4=6, so the area of β³ADB is 52ββ
6=12/5.
Answer: Dβ.
The problems on this page are the property of the MAA's American Mathematics Competitions