Problem:
What is the value of 1+3+5+...+2017+2019β2β4β6β...2016β2018?
Answer Choices:
A. β1010
B. β1009
C. 1008
D. 1009
E. 1010
Solution:
Rearranging the terms, notice that the expression in the question is equal to:
β(1+3β2)+(5β4)+β―+(2017β2016)+(2019β2018)β
Each term is equal to 1, and there are 22019β1ββ1=1010 terms, so the total sum is
1010β
1=1010.
Thus, E is the correct answer.
Answer: Eβ.
The problems on this page are the property of the MAA's American Mathematics Competitions