Problem:
What is the value of the product below?
(2β
21β
3β)(3β
32β
4β)(4β
43β
5β)β―(98β
9897β
99β)(99β
9998β
100β)
Answer Choices:
A. 21β
B. 9950β
C. 98019800β
D. 99100β
E. 50
Solution:
We can regroup all the numbers as follows:
1β
(2β
33β
2β)(3β
44β
3β)β¦(98β
9999β
98β)β
99100β
From this representation, we can see that all the middle terms cancel, leaving only
21ββ
99100β=9950β.
Thus, the correct answer is B.
Answer: Bβ.
The problems on this page are the property of the MAA's American Mathematics Competitions