Problem:
Rectangle ABCD is inscribed in a semicircle with diameter FE, as shown in the figure. Let DA=16 and FD=AE=9. What is the area of ABCD?
Answer Choices:
A. 240
B. 248
C. 256
D. 264
E. 272
Solution:
Let O be the center of the circle. Then DO=OA=8 and radius OE=OA+AE=8+9=17. Draw radius OB which also has length 17. Then β³OAB is a right triangle with hypotenuse 17 and base leg 8. By the Pythagorean Theorem AB=172β82β=289β64β=225β=15. The area of rectangle ABCD is DAβ AB = 16β 15 = 240.