Problem:
What is the value of:
Answer Choices:
A.
B.
C.
D.
E.
Solution:
Since every integer from to occurs once as a denominator and once as a numerator, they cancel each other out. After canceling every number out, we have only and left as numerators and and left as denominators. The remaining fraction is . This simplifies to .
Answer: .
The problems on this page are the property of the MAA's American Mathematics Competitions