Problem: In △ABC,AC=24′′,BC=10′′, and AB=26′′. The radius of the inscribed circle is:
Answer Choices:
A. 26 in.
B. 4 in.
C. 13 in.
D. 8 in.
E. none of these answers
Solution:
For any right triangle we have a−r+b−r=c where r is the radius of the inscribed circle.
∴2r∴r​=a+b−c=24+10−26=8;=4.​