Problem: The value of 161​a0+(16a1​)0−(64−1/2)−(−32)−4/5 is:
Answer Choices:
A. 11613​
B. 1163​
C. 1
D. 87​
E. 161​
Solution:
x0=1 for any number x(xî€ =0) and −32=−25.
∴161​+1−64​1​−(−25)1/51​=161​+1−81​−161​=87​.