Problem: The hypotenuse of a right triangle is 101010 inches and the radius of the inscribed circle is 111 inch. The perimeter of the triangle in inches is:
Answer Choices:
A. 151515
B. 222222
C. 242424
D. 262626
E. 303030 Solution:
c=a−r+b−rc=a-r+b-rc=a−r+b−r. ∴10=a+b−2\quad \therefore 10=a+b-2∴10=a+b−2; ∴P=a+b+c=10+2+10=22\therefore P=a+b+c=10+2+10=22∴P=a+b+c=10+2+10=22.