Problem: The length of rectangle R is 10 per cent more than the side of square S. The width of the rectangle is 10 per cent less than the side of the square. The ratio of the areas, R:S, is:
Answer Choices:
A. 99:100
B. 101:100
C. 1:1
D. 199:200
E. 201:200
Solution:
The dimensions of R are 1.1s and 0.9s; its area is 0.99s2. ∴R/S=.99s2/s2=99/100.