Problem: Comparing the numbers 10−49 and 2⋅10−50 we may say:
Answer Choices:
A. the first exceeds the second by 8⋅10−1
B. the first exceeds the second by 2⋅10−1
C. the first exceeds the second by 8⋅10−50
D. the second is five times the first
E. the first exceeds the second by 5
Solution:
10−49=10⋅10−50;∴10−49−2⋅10−50=10−50(10−2)=8⋅10−50.