Problem: The numbers x,y,zx, y, zx,y,z are proportional to 2,3,52,3,52,3,5. The sum of x,yx, yx,y, and zzz is 100100100. The number yyy is given by the equation y=ax−10y=a x-10y=ax−10. Then a is:
Answer Choices:
A. 222
B. 3/23 / 23/2
C. 333
D. 5/25 / 25/2
E. 444 Solution:
The numbers are easily found to be 20,30 and 50.∴30=20a−1050 . \quad \therefore 30=20 a-1050.∴30=20a−10; ∴a=2\therefore a=2∴a=2.